A number juggling succession barisan geometri is portrayed by having a typical contrast, d.
Let T(1) = a be the initial term, d be the normal distinction and T(n) be the overall term of a math succession.
At that point d = T(2) – T(1) = T(3) – T(2)
= … . = T(n) – T(n-1)
We like to draw as in the graph
T(1) = a, T(2) = a +d , … ., T(n).
The directions of the top purposes of vertical lines are (1, a), (2, a+d), … .. , (n,T(n)).
By thinking about the angle of the initial two focuses,
Since the given arrangement is number-crunching, the red line is candid with angle d.
On the off chance that we discover the slope of the line utilizing the first and the last point, (1, an) and (n, T(n)),
In the number-crunching arrangement 9, 1, – 15, … . , locate the twentieth term.
Let A(1,9), B(2,1) and C(20, T(20)).
The three focuses A, B, C are collinear.
\ T(20) = – 143.
Supplement 6 number-crunching implies between the numbers – 18 and 3.
Consider the focuses A(1, – 18) and B(8, 3).
\ The 6 number juggling implies are – 15, – 12, – 9, – 6, – 3, 0.
In the number juggling succession the fourth term is 10, the seventh term is 19.
Locate the basic distinction d and the twentieth term
Let A(4, 10), B(7, 19), C(20, T(20))
\ T(20) = 58.
In the number juggling succession T(p) = q and T(q) = p, where p ≠ q. Discover T(p+q).
Let A(p, q), B(q,p), C(p+q, T(p+q)).
A, B and C are collinear.
\ and we have
Unraveling, we get T(p+q) = 0.
We can utilize “territory” formulae for ascertaining the quantities of specks in the charts:
(1) Applying the “region” of square shape:
Number of spots = 3 x 4 = 12
(2) Applying the “region” of trapezium,
Number of spots
As should be obvious, the formulae of region of triangle, square shape, trapezium and so on can be utilized in tallying the quantity of dabs if the spots are masterminded in a grid design.
Let S(n) = T(1) + T(2) + … + T(n) be the total of the particulars of the number juggling succession and we get a math arrangement.
Presently, study the outline morally justified:
The principal vertical section of spots speaks to T(1).
The last vertical section of dabs speaks to T(n).
There are by and large n segments.
S(n) is the whole of all segments of dabs and we can apply the region equation for trapezium.